Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
5. Quadratic Equations
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Exercise 31 Page 229

First rewrite the equation in standard form.

x=- 1 and x=0.25

Practice makes perfect
To solve the equation using our calculator, we first have to rewrite the equation in standard form.
1=4x^2+3x
0=4x^2+3x-1
Having rewritten the equation in standard form, we can enter it in the calculator by pushing Y= and writing the non-zero side in the first row.
Window with inequality

Next, by pushing GRAPH, the calculator will draw the graph of the equation. Note that we are looking for x-values that make the y-value equal 0.

Window with a graph

Let's zoom in, so that we can see the zeros better. To do this, push WINDOW and change the settings to a much smaller window. Then push GRAPH once more to draw the equation with these new settings.

Solutiobn64600 3.svg
Window with a graph

We are able to see that the graph intersects the x-axis twice and there are two zeros. To find them, we can use the zero option in the calculator. This can be found by pressing 2ND and then CALC.

Solution64600 5.svg

After selecting the "zero" option, we need to choose left and right boundaries for one of the zeros. Finally, the calculator asks for a guess where the zero might be. After that, it will calculate the exact point for us. We will have to do this twice, once for each zero.

Window with a graph
Window with a graph

This equation's solutions are x=- 1 and x=0.25.