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Pearson Algebra 2 Common Core, 2011 View details

5. Systems With Three Variables

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Exercise 35 Page 172

Can you manipulate the coefficients of any variable terms such that they could be eliminated?

(1/2,2,-3)

Practice makes perfect

The given system consists of equations of planes. Let's use the Elimination Method to find a solution to this system. Notice that in the third equation there is no x-term. 4x-y+2z=-6 & (I) -2x+3y-z=8 & (II) 2y+3z=-5 & (III) By manipulating the first equation and adding it to the second equation, we can solve for y.

4x-y+2z=-6 & (I) -2x+3y-z=8 & (II) 2y+3z=-5 & (III)

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(II): Solve by elimination

MultEqn

(II):LHS * 2=RHS* 2

4x-y+2z=-6 -4x+6y-2z=16 2y+3z=-5

SysEqnAdd

(II): Add (I)

4x-y+2z=-6 -4x+6y-2z+( 4x-y+2z)=16+( -6) 2y+3z=-5

RemovePar

(II): Remove parentheses

4x-y+2z=-6 -4x+6y-2z+4x-y+2z=16-6 2y+3z=-5