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When using the Substitution Method to solve a system of equations, it is necessary to isolate a variable.
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The given system consists of equations of planes. When using the Substitution Method to solve a system of equations, it is necessary to isolate a variable. In the first equation, y is isolated, so we will start by substituting it for its equivalent expression into the remaining equations.
(II), (III): y= -2x+10
(II): Remove parentheses
(III): Distribute -2
(II), (III): Add and subtract terms
(II): LHS+2z=RHS+2z
(II): LHS+2=RHS+2
(II): LHS * 2=RHS* 2
(II):Rearrange equation
(III): 4z= -6x+24
(III): Remove parentheses
(III): Add and subtract terms
(III):LHS-4=RHS-4
The value of x is 3. Substituting 3 for x into the first and the second equations, we can find the values of x and z.
(I), (II): x= 3
(I), (II): Multiply
(I), (II): Add terms
(II):.LHS /4.=.RHS /4.
(II): a/b=.a /2./.b /2.
The value of z is 32.