Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
5. Systems With Three Variables
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Exercise 42 Page 172

Begin by determining the unknowns. Then, make an organized table to write the system.

Amount in a Savings Account: $2200
Amount in Government Bonds: $4400
Amount in a Mutual Fund: $3400

Practice makes perfect

We will begin by determining the unknowns. Amount in a Savings Account:& x Amount in Government Bonds:& 2 x Amount in a Mutual Fund:& y Now that the unknowns have been determined, we can use an organized table to write the equations.

Verbal Expression Algebraic Expression
The bonus received is $10 000. x+2 x+ y=10 000
Income from the investments is $455. ( 4.5 %) x+( 5 %)2 x+( 4 %) y=455
Let's rewrite the percentages from the second equation as percent proportions. (4.5 %)x+(5 %)2x+(4 %)y=455 & ⇓ 4.5100x+( 5100)2x+ 4100y=455 We have two equations to form a system of equations. x+2x+y=10 000 & (I) 4.5100x+( 5100)2x+ 4100y=455 & (II) Because none of the terms is isolated, using the Elimination Method will be more efficient than using the Substitution Method.
x+2x+y=10 000 & (I) 4.5100x+( 5100)2x+ 4100y=455 & (II)
x+2x+y=10 000 & (I) 4.5100x+ 5(2)100x+ 4100y=455 & (II)
x+2x+y=10 000 4.5100x+ 10100x+ 4100y=455
x+2x+y=10 000 4.5(100)100x+ 10(100)100x+ 4(100)100y=45 500
x+2x+y=10 000 4.5x+10x+4y=45 500

(I), (II): Add terms

3x+y=10 000 14.5x+4y=45 500
-12x-4y=-40 000 14.5x+4y=45 500
-12x-4y=-40 000 14.5x+4y -12x-4y=45 500 -40 000
-12x-4y=-40 000 2.5x=5500
-12x-4y=-40 000 x=2200
Now that we have found the value of x, we can find the value of y by substituting 2200 for x into the first equation.
-12x-4y=-40 000 x=2200
3x+y=10 000 x=2200
3( 2200)+y=10 000 x=2200
6600+y=10 000 x=2200
y=3400 x=2200
Let's now use the value of x to find out the amount in government bonds.
2x
2( 2200)
4400
Finally, we can write the amount of money in each account and bond. Amount in a Savings Account:& $2200 Amount in Government Bonds:& $4400 Amount in a Mutual Fund:& $3400