Sign In
Start by identifying the values of a, b, and c.
To draw the graph of the given quadratic function written in standard form, we must start by identifying the values of a, b, and c. y=3x^2-20x ⇔ y=3x^2+(-20)x+ We can see that a=3, b=-20, and c= . Now, we will follow four steps to graph the function.
The axis of symmetry is a vertical line with equation x=- b2a. Since we already know the values of a and b, we can substitute them into the formula.
The axis of symmetry of the parabola is the vertical line with equation x= 103, or x=3 13.
To calculate the vertex, we need to think of y as a function of x, y=f(x). We can write the expression for the vertex by stating the x- and y-coordinates in terms of a and b. Vertex: ( - b/2a, f( - b/2a ) ) Note that the formula for the x-coordinate is the same as the formula for the axis of symmetry, which is x= 103. Thus, the x-coordinate of the vertex is also 103. To find the y-coordinate, we need to substitute 103 for x in the given equation.
x= 10/3
(a/b)^m=a^m/b^m
a*b/c= a* b/c
a/b=.a /3./.b /3.
Subtract fractions
The y-coordinate of the vertex is - 1003, or - 33 13. Therefore, the vertex is ( 103,- 1003), or (3 13,- 33 13).
The y-intercept of the graph of a quadratic function written in standard form is given by the value of c. Thus, the point where our graph intercepts the y-axis is (0, ). Let's plot this point and its reflection across the axis of symmetry.
We can now draw the graph of the function. Since a=3, which is positive, the parabola will open upwards. Let's connect the three points with a smooth curve.