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Start by identifying the values of a, b, and c.
Graph:
Axis of Symmetry: x=2
Vertex: (2,17)
To draw the graph of the given quadratic function written in standard form, we must start by identifying the values of a, b, and c. y=- 2x^2+8x+9 ⇔ y= - 2x^2+ 8x+ 9 We can see that a= - 2, b= 8, and c= 9. Now, we will follow four steps to graph the function.
The axis of symmetry is a vertical line with equation x= - b2 a. Since we already know the values of a and b, we can substitute them into the formula.
The axis of symmetry of the parabola is the vertical line with equation x=2.
To calculate the vertex, we need to think of y as a function of x, y=f(x). We can write the expression for the vertex by stating the x- and y-coordinates in terms of a and b. Vertex: ( - b/2 a, f( - b/2 a ) ) Note that the formula for the x-coordinate is the same as the formula for the axis of symmetry, which is x=2. Therefore, the x-coordinate of the vertex is also 2. To find the y-coordinate, we need to substitute 2 for x in the given equation.
We found the y-coordinate, and now we know that the vertex is (2,17).
The y-intercept of the graph of a quadratic function written in standard form is given by the value of c. Thus, the point where our graph intercepts the y-axis is (0, 9). Let's plot this point and its reflection across the axis of symmetry.
We can now draw the graph of the function. Since a= - 2, which is negative, the parabola will open downwards. Let's connect the three points with a smooth curve.