Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
2. Quadratic Functions
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Exercise 32 Page 557

Practice makes perfect
a We will start this part of the exercise by plotting points for the parent function then use those points to graph the transformation.

Parent Function

We will use a 3 step approach to graphing the parent function.

  1. Find the axis of symmetry and vertex
  2. Find two other points
  3. Graph

Vertex

Our parent function, f(x)=x^2+2x-3, is already in standard form, y= ax^2+ bx+ c, so we can go directly to finding the axis of symmetry.

x=- b/2 a In our function, f(x)=x^2+2x-3, we can substitute a= 1, b= 2, and c= 3 into the formula for the axis of symmetry.
x=- b/2 a
x=-( 2)/2( 1)
â–Ľ
Calculate x
x=-2/2
x=-1
The axis of symmetry gives us the x-coordinate for vertex, x=-1. To find the y-coordinate we substitute the x=-1 into the function.
f(x)=x^2+2x-3
f(x)=( -1)^2+2( -1)-3
â–Ľ
Calculate f(x)
f(x) = 1 + 2(-1)-3
f(x) = 1-2-3
f(x)=-4
From this, we can conclude that our vertex is (-1,-4).

Other Points

Three non-linear points define a parabola, so we only need two additional points to graph this function. Let's make a table of values.

x f(x)=x^2+2x-3 y=f(x)
0 0^2+2( 0)-3 -3
2 2^2+2( 2)-3 5

Now we have the additional points (0,-3) and (2,5). Let's look at the graph.

Plotting Points

We can start this graph by plotting the three points that we have, adding in the axis of symmetry, adding in symmetric points, then connecting the points with the parabola.

Transformation f(x)+3

Let's first look at what kind of transformation we have.

Transformations of f(x)
Vertical Translations Translation up k units, k>0 y=f(x)+ k
Translation down k units, k>0 y=f(x)- k

Our function, f(x)+ 3, looks most like an vertical translation upward. We can see that the + 3 will shift the function up 3 units. Let's add 3 to each of the y-coordinates of our three points from our parent function and see what this transformation does to them.

(x,f(x)) (x,f(4x))
(-1,-4) (-1,-1)
(0,-3) (0,0)
(2,5) (2,8)

Let's plot these points with our parent function, then move the mirrored points up as well.

b We can graph our parent function like in Part A, then plot the transformed points below. Let's first look at what kind of transformation we have.

Transformations of f(x)
Vertical Stretch or Compression Vertical stretch, a>1 y= af(x)
Vertical compression, 0< a< 1 y= af(x)

Our function, 2[f(x)], looks most like a vertical stretch. The 2[f(x)] stretches the function up and down by a factor of 2. Let's have a look at our three points from our original function and multiply the y-coordinates by 2.

(x,f(x)) (x,2[f(x)])
(-1,-4) ( -1,-8)
(0,-3) ( 0,-6)
(2,5) ( 2,10)

Let's plot those points and the mirrored points from the parent function.


c We will plot the parent function from Part A, and, then, the transformation. Let's first look at what kind of transformation we have.


Transformations of f(x)
Horizontal Stretch or Compression Horizontal stretch, 0< b<1 y=f( bx)
Horizontal compression, b>1 y=f( bx)

Our function, f( 4x), is a horizontal compression and shrinks the function by a factor of 4. When a transformation is inside the parentheses with the x, then the transformation affects the x-axis in the opposite way of the operation on x. Let's divide each x-coordinate by our three points from our parent function by 4.

(x,f(x)) (x/4,f(x))
(-1,-4) ( -1/4,-4)
(0,-3) ( 0,-3)
(2,5) ( 1/2,5)

Let's plot those points and the mirrored points from the original function.

d For this part of the exercise, we will graph the parent function, and, then, plot the corresponding points for the transformation. Let's first look at what kind of transformation we have.
Transformations of f(x)
Horizontal Translations Translation right h units, h>0 y=f(x- h)
Translation left h units, h>0 y=f(x+ h)

Our function, f(x+ 5), is a horizontal shift that shifts the function to the left by 5 units. When a transformation is inside the parentheses with the x, then the transformation affects the x-axis in the opposite way of the operation on x. Let's subtract 5 from each x-coordinate of the three points from our parent function in Part A.

(x,f(x)) (x-5,f(x))
(-1,-4) ( -6,-4)
(0,-3) ( -5,-3)
(2,5) ( -3,5)

Let's plot those points and the mirrored points from the original function.

Extra

Summary
Let's summarize what we found.