Exercise 63 Page 300

To find certain terms in a sequence described by an explicit rule, substitute the number of the desired term into the formula to get the term's value. The given explicit formula is as follows. A(n)=- 5+(n-1)(6)We can find the second, fourth, and tenth terms of the sequence by substituting 2, 4, and 10 into the formula for n.

A(n)=- 5+(n-1)(6)

Substitute

n= 2

A( 2)=- 5+( 2-1)(6)

SubTerm

Subtract term

A(2)=- 5+(1)(6)

IdPropMult

Identity Property of Multiplication

A(2)=- 5+6

AddTerms

Add terms

A(2)=1

We have found that the second term of the sequence is 1. Now, let's construct a table and do the same thing for the fourth and tenth terms.

n^(th) Term	- 5+(n-1)(6)	A(n)
2	- 5+( 2-1)(6)	1
4	- 5+( 4-1)(6)	13
10	- 5+( 10-1)(6)	49

The second, fourth, and tenth terms are 1, 13, and 49.