Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
8. Unions and Intersections of Sets
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Exercise 56 Page 220

Isolate the absolute value.

x=4/3 or x=-4/3

Practice makes perfect
Before we can solve the given equation, we need to isolate the absolute value expression using the Properties of Equality. 2|3x|+1=9 ⇒ |3x|=4 An absolute value measures an expression's distance from a midpoint on a number line. |3x|=4 This equation means that the distance between x and 0 is 4, either in the positive direction or the negative direction. |3x|=4 ⇒ l3x= 4 3x= - 4 To find the solutions to the absolute value equation, we need to solve both of these cases for x.
| 3x|=4

lc 3x ≥ 0:3x = 4 & (I) 3x < 0:3x = - 4 & (II)

lc3x=4 & (I) 3x=- 4 & (II)

(I), (II): .LHS /3.=.RHS /3.

lx= 43 x= - 43
lx= 43 x=- 43