8. Unions and Intersections of Sets
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Isolate the absolute value on the left-hand side.
y=4/3 or y=-8/3
Before we can solve the given equation, we need to isolate the absolute value expression using the Properties of Equality.
3|3y+2|=18 ⇒ |3y+2|=6
An absolute value measures an expression's distance from a midpoint on a number line.
lc 3y+2 ≥ 0:3y+2 = 6 & (I) 3y+2 < 0:3y+2 = - 6 & (II)
(I), (II): LHS-2=RHS-2
(I), (II): .LHS /3.=.RHS /3.