8. Unions and Intersections of Sets
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Isolate the absolute value on the left-hand side. How many cases do you have after you remove it?
f=2 or f=8
Before we can solve the given equation, we need to isolate the absolute value expression using the Properties of Equality.
4|f-5|=12 ⇒ |f-5|=3
An absolute value measures an expression's distance from a midpoint on a number line.
lc f-5 ≥ 0:f-5 = 3 & (I) f-5 < 0:f-5 = - 3 & (II)
(I), (II): LHS+5=RHS+5