Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
8. Unions and Intersections of Sets
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Exercise 55 Page 220

Create an or compound inequality because the absolute value is greater than or equal to the given value.

w<- 15 or w>9

Practice makes perfect
We are asked to find the solution set for all possible values of w in the given inequality. |2w+6|>24 To do this, we will create a compound inequality by removing the absolute value. In this case, since 2w+6 can be written as 2w-(-6), the solution set contains the numbers that make the distance between 2w and - 6 greater than 24 in the positive direction or in the negative direction.

2w+6 > 24 or 2w+6<- 24 Let's isolate w in both of these cases.

Case 1

2w+6>24
2w>18
w>9
This inequality tells us that all values greater than 9 will satisfy the inequality.

Case 2

2w+6<- 24
2w<- 30
w<- 15
This inequality tells us that all values less than - 15 will satisfy the inequality.

Solution Set

The solution to this type of compound inequality is the combination of the solution sets. First Solution Set:& w>9 Second Solution Set:& w<- 15 Combined Solution Set:& w<- 15 or w>9