Exercise 26 Page 211

An absolute value measures an expression's distance from a midpoint on a number line. For this exercise, we need to isolate the absolute value before we can find this distance.

|3t-2|+6=2

SubEqn

LHS-6=RHS-6

|3t-2|+6-6=2-6

SubTerms

Subtract terms

|3t-2|=-4

Since distance cannot be negative, the absolute value of a number cannot be negative. |3t-2|= -4 An absolute value cannot be equal to -4, so this equation has no solution.