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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

7. Absolute Value Equations and Inequalities

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Exercise 20 Page 211

How many cases do you have after you remove the absolute value?

m=1 or m=-5

Practice makes perfect

An absolute value measures an expression's distance from a midpoint on a number line. 3=|m+2| ⇒ |m+2|= 3This equation means that the distance is 3, either in the positive direction or the negative direction. |m+2|= 3 ⇒ lm+2= 3 m+2= -3 To find the solutions to the absolute value equation, we need to solve both of these cases for m.

| m+2|=3

lc m+2 ≥ 0:m+2 = 3 & (I) m+2 < 0:m+2 = - 3 & (II)

lcm+2=3 & (I) m+2=-3 & (II)

(I), (II): LHS-2=RHS-2

lm_1=1 m_2=-5

Both 1 and -5 are solutions to the absolute value equation.

Subchapter links

Lesson Check p.210

Practice and Problem-Solving Exercises p.211-213

Standardized Test Prep p.213

Mixed Review p.213