Exercise 10 Page 659

We want to completely factor the given expression. Here we have a quadratic trinomial of the form ax^2+bx+c, where |a| ≠ 1 and there are no common factors. To factor this expression, we will rewrite the middle term, bx, as two terms. The coefficients of these two terms will be factors of ac whose sum must be b. 3x^2+2xy-8y^2 ⇔ 3x^2+(2)xy+(-8)y^2 We know that a= 3, b=2, and c=-8. There are now three steps we need to follow in order to rewrite the above expression.

1. Find a c. Since we have that a= 3 and c=- 8, the value of a c is 3* (-8)=- 24.
2. Find factors of a c. Since ac=- 24, which is negative, we need factors of a c to have opposite signs — one positive and one negative — in order for the product to be negative. Since b=2, which is positive, the absolute value of the positive factor will need to be greater than the absolute value of the negative factor, so that their sum is positive.

c|c|c|c 1^(st)Factor &2^(nd)Factor &Sum &Result 24 &- 1 &24 + (-1) &23 12 &- 2 &12 + (-2) &10 8 &- 3 &8 + (-3) &5 6 & - 4 & 6 + ( -4) &2 4 &- 8 &4 + (-8) &- 4 2 &- 12 &2 + (-12) &- 10 1 &- 24 &1 + (-24) &- 23

3. Rewrite bx as two terms. Now that we know which factors are the ones to be used, we can rewrite bx as two terms. 3x^2+2xy-8y^2 ⇔ 3x^2 + 6xy - 4xy-8y^2

Finally, we will factor the last expression obtained.

Checking the Solutions

We can expand our answer and compare it with the given expression.

We can see above that after expanding and simplifying, the result is the same as the given expression. Therefore, the correct answer is H.