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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

Cumulative Standards Review

Exercise 15 Page 660

Solve for the variable by using the Cross Products Property.

4

Practice makes perfect

To solve the proportion, we will start by using the Cross Products Property. Remember that we will need to treat -3(a-2) as a single quantity in the cross multiplication process.

- a/4=-3(a-2)/6

Cross multiply

6(- a)=4(-3)(a-2)

a(- b)=- a * b

- 6(a)=- 4(3)(a-2)

Multiply

- 6a=-12(a-2)

From here, we will continue solving for a by using the Distributive Property and the Properties of Equality.

- 6a=-12(a-2)

Distribute -12

- 6a=-12a+24

LHS+12a=RHS+12a

6a=24

.LHS /6.=.RHS /6.

a=4