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Solve the related quadratic equation, plot the solutions on a number line, and test a value from each interval.
{ x|0.75 ≤ x ≤ 4}
To solve the quadratic inequality algebraically, we will follow three steps.
We will start by solving the related equation.
4x^2-19x=- 12
⇕
4x^2+( - 19)x+ 12=0
Substitute values
Now we can calculate the first root using the positive sign and the second root using the negative sign.
| x = 19 ± 13/8 | |
|---|---|
| x = 19 + 13/8 | x = 19 - 13/8 |
| x = 32/8 | x = 6/8 |
| x = 4 | x = 0.75 |
The solutions of the related equation are 4 and 0.75. Let's plot them on a number line. Since the original is not a strict inequality, the points will be closed.
Finally, we must test a value from each interval to see if it satisfies the original inequality. Let's choose a value from the first interval, x ≤ 0.75. For simplicity, we will choose x=- 1.
x= - 1
Calculate power
- a(- b)=a* b
Add terms
Since x=- 1 did not produce a true statement, the interval x ≤ 0.75 is not part of the solution. Similarly, we can test the other two intervals.
| Interval | Test Value | Statement | Is It Part of the Solution? |
|---|---|---|---|
| 0.75 ≤ x ≤ 4 | 1 | - 15 ≤ - 12 ✓ | Yes |
| x ≥ 4 | 5 | 5 ≰ - 12 * | No |
We can now write the solution set and show it on a number line. { x|0.75 ≤ x ≤ 4} or [ 0.75, 4 ]