x=- b±sqrt(b^2-4ac)/2a
Having the equation written in standard form, we can now identify the values of a, b, and c.
2x^2+3x-18=0 ⇔ 2x^2+ 3x+( -18)=0
Let's evaluate the discriminant.
b If we want to know the number of real solutions we only need to work with the discriminant. Remember that if the discriminant is greater than zero, the equation will have two real solutions. If it is equal to zero, the equation will have one real solution. Finally, if the discriminant is less than zero, the equation will have no real solutions.
b^2-4ac= 153
Since the discriminant is 153, the quadratic equation has two real roots.
ax^2+ bx+ c=0 ⇔ x=- b± sqrt(b^2-4 a c)/2 a
We know that a= 2, b= 3, c= -18, and that the discriminant b^2-4ac= 153. Let's substitute these values into the Quadratic Formula.
Using the Quadratic Formula, we found that the solution of the given equation is x= -3 ± sqrt(153)4. There are two irrational real solutions, x= -3 - sqrt(153)4 and x= -3 + sqrt(153)4.
