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Identify the vertex first. Then use it to find the axis of symmetry.
Vertex Form: f(x)=2(x+3)^2-26
Vertex: (-3,-26)
Axis of Symmetry: x=-3
Opening: Opens up
Graph:
We want to draw the graph of the given quadratic function. To do so, we will rewrite it in vertex form, f(x)=a(x-h)^2+k, where a, h, and k are either positive or negative numbers. To draw the graph, we will follow four steps.
Let's get started.
We have a quadratic function written in standard form, and we want to rewrite it in vertex form.
Standard Form:& y= ax^2+ bx+ c
Given Equation:& y= 2x^2+ 12x- 8
So far, we know that the vertex lies at (-3,k). To find the y-coordinate k, we will substitute -3 for x in the given function.
x= -3
Calculate power
a(- b)=- a * b
Multiply
Add and subtract terms
Therefore, the (h,k) coordinate pair of the vertex is ( -3, -26). Recall that if a<0, the parabola will open downwards. Conversely, if a>0, the parabola will open upwards. Since we know that a= 2, h= -3, and k= -26 we can write it in vertex form. Since a is greater than 0, the parabola will open upwards. Vertex Form:& f(x)= a(x- h)^2+ k Function:& f(x)= 2(x+ 3)^2- 26
Let's now plot the vertex ( h, k) and draw the axis of symmetry x= h. Since we already know the values of h and k, we know that the vertex is ( -3, -26). Therefore, the axis of symmetry is the vertical line x= -3.
We will now plot a point on the curve by choosing an x-value and calculating its corresponding y-value. Let's try x=0.
When x=0, we have y=-8. As such, the point (0,-8) lies on the curve. Let's plot this point and reflect it across the axis of symmetry.
Notice that both points have the same y-coordinate.
Finally, we will sketch the parabola which passes through the three points. Remember not to use a straightedge for this!