Exercise 26 Page 62

Before we calculate the perimeter and area, let's draw a diagram of the figure with the given coordinates.

Drawing a Diagram

We will start by plotting the points on a coordinate plane. We can see three sides, so this is a triangle.

We can see that KL is vertical and JL is horizontal. This information will help in finding the distance between K and L, J and L, and also in finding the area of the triangle.

Finding the Perimeter

The perimeter is the sum of the length of the sides. Since KL is vertical, we can find the distance between K and L by counting squares. KL=5 Similarly, since JL is horizontal, we can also find the distance between J and L by counting squares. JL=6 To find the length of the last side, we can use the Distance Formula.

JK=sqrt((x_2-x_1)^2+(y_2-y_1)^2)

SubstitutePoints

Substitute ( - 3,- 3) & ( 3,2)

JK=sqrt(( 3-( - 3))^2+( 2-( - 3))^2)

▼

Simplify

SubNeg

a-(- b)=a+b

JK=sqrt((3+2)^2+(2+3)^2)

AddTerms

Add terms

JK=sqrt(5^2+5^2)

CalcPow

Calculate power

JK=sqrt(25+25)

AddTerms

Add terms

JK=sqrt(50)

Finally, we can find the perimeter by adding the lengths of the sides. 5+6+sqrt(50)≈ 18.07units

Finding the Area

From the figure, we can find that the base is JL=6 and the height is KL=5. Now we can use the formula for the area of a triangle.

A=1/2bh

SubstituteII

b= 6, h= 5

A=1/2( 6)( 5)

Multiply

Multiply

A=15

The area of the triangle is 15units^2.