McGraw Hill Glencoe Geometry, 2012
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McGraw Hill Glencoe Geometry, 2012 View details
6. Two-Dimensional Figures
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Exercise 48 Page 63

Compare the area of the room and of the tiles. Be careful with the units.

Number of Tiles: 1440
Explanation: See solution.

Practice makes perfect

Note that the dimensions of the room and the tiles are given in different units. To compare the areas, we first must convert the measurements of the room to inches. Recall that there are 12 inches in a foot.

Side Measurement
In feet In inches
Length 20 20* 12=240
Width 12.5 12.5* 12=150

Calculating the area of the room.

To find the area of the room, we can use the formula for the area of a rectangle in terms of its length l and width w. A=l wWe calculate the area in square inches.
A=l w
A=( 240)( 150)
A=36000
The floor area of the room is 36000 square inches.

Calculating the area of a tile.

Let's see now how much we can cover with a single 5-inch square tile. The find the area of a tile, we can use the formula for the area of a square in terms of its side length, s. A=s^2 We calculate the area in square inches.
A=s^2
A= 5^2
A=25
The area of a single tile is 25 square inches.

Answering the question.

Since one tile covers 25 square inches and we need to cover 36000 square inches, we need at least 36000/25=1440 tiles. You can see these 1440 tiles covering the floor on the figure below.

Alternative Solution

Alternative way of thinking

Instead of investigating areas, we can try to cover the room with the tiles starting from the sides. Let's think of how many 5-inch square tiles we need in a line to fill the length of the sides.

Side Measurement in inches Tiles needed
Length 240 240/5=48
Width 150 150/5=30

This means that in a rectangular pattern we need 30 rows of tiles with 48 tiles in each row to cover the floor of the room. Thus, we need 30* 48=1440 tiles.