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McGraw Hill Glencoe Algebra 1, 2012

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McGraw Hill Glencoe Algebra 1, 2012 View details

4. Parallel and Perpendicular Lines

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Exercise 64 Page 245

Substitute the given point and slope into the slope-intercept form of an equation.

y=-3x-10

Practice makes perfect

Equations in slope-intercept form follow a certain format. y= mx+ b In this form, m is the slope and b is the y-intercept. The line has a slope of - 3 which means that we can substitute m= - 3. y= - 3x+ b By substituting the given point ( -3, -1) into the above equation for x and y, we can solve for y-intercept b.

y=- 3x+b

x= - 3, y= - 1

- 1=- 3( - 3)+b

▼

Solve for b

MultNegNegOnePar

- a(- b)=a* b

- 1=9+b

LHS-9=RHS-9

- 10=b

Rearrange equation

b= - 10

Now that we have both the slope and the y-intercept, we can write the final equation. y= - 3x+( - 10) ⇔ y= - 3x - 10

Subchapter links

Check Your Understanding p.242

Practice and Problem Solving p.243-244

H.O.T. Problems p.244

Standardized Test Practice p.245

Spiral Review p.245

Skills Review p.245