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Recall the Zero Exponent Property and the Negative Exponent Property.
&* (3/x^2)^0 &âś“ x^0/3^2 &* 1/6^(- x) &* 1/x^(-3) &âś“ 3x^(-4)
We are asked to find which of the given expressions have values less than 1 when x=4. & (3/x^2)^0 & x^0/3^2 & 1/6^(- x) & 1/x^(-3) & 3x^(-4) To do that we will evaluate them one at a time, starting with ( 3x^2)^0.
To evaluate the first expression, let's start with substituting x= 4. (3/x^2)^0=(3/4^2)^0 Now, let's recall the Zero Exponent Property.
Zero Exponent Property |
Any non-zero real number raised to the power of 0 is equal to 1. a^0=1 |
Notice that the expression ( 34^2)^0 is a non-zero real number raised to the power of 0. Therefore, according to the Zero Exponent Property, the expression must be equal to 1. (3/4^2)^0=1 Since 1 is not less than 1, we can note that the expression ( 3x^2)^0 does not have a value less than 1 when x=4. &* (3/x^2)^0 & x^0/3^2 & 1/6^(- x) & 1/x^(-3) & 3x^(-4)
x^0/3^2=4^0/3^2 Now we can use the Zero Exponent Property again. 4^0/3^2=1/3^2 Finally, we can simplify the denominator. 1/3^2=1/9 We found that when x=4 the expression x^03^2 is equal to 19, which is less than 1. &* (3/x^2)^0 &âś“ x^0/3^2 & 1/6^(- x) & 1/x^(-3) & 3x^(-4)
Let's evaluate 16^(- x). As before, we will first substitute x= 4. 1/6^(- x)=1/6^(- 4) Next, let's recall the Negative Exponent Property.
Negative Exponent Property |
If a is a non-zero real number, then the following equation is true. a^(- n)=1/a^n |
a/1=a
a * 1=a
Rewrite 6^4 as 6*6*6*6
Multiply
a/1=a
a * 1=a
Rewrite 4^3 as 4*4*4
Multiply
a*b/c= a* b/c
Rewrite 4^4 as 4*4*4*4
Multiply