Core Connections Integrated II, 2015
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Core Connections Integrated II, 2015 View details
3. Section 9.3
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Exercise 91 Page 514

Practice makes perfect
a We want to write an equation representing the relationship between x, y and r. Let's consider the given diagram.

It depicts a right triangle. Notice that x is the length of leg adjacent to angle θ and y is the length of leg opposite angle θ. We can relate those terms using the tangent ratio. tan(θ)=opposite/adjacent Let's substitute y for opposite and x for adjacent to obtain the sought relationship. tan(θ)=y/x

b Consider the given diagram.
Now, let's recall that in a right triangle, sine of an acute angle is the ratio of lengths of leg opposite that angle and the hypotenuse.

sin( θ) = opposite/hypotenuse In our case, the lengths of the opposite leg and the hypotenuse are y and r, respectively. sin( θ) = y/r Finally, let's consider this expression for r = 1. sin( θ) = y/1 = y. Therefore, when r = 1, we have sin( θ) =y.

c Consider the given diagram.
Now, let's recall that in a right triangle, cosine of an acute angle is the ratio of lengths of leg adjacent to that angle and the hypotenuse.

cos( θ) = adjacent/hypotenuse In our case, the lengths of the adjacent leg and the hypotenuse are x and r, respectively. cos( θ) = x/r Finally, let's consider this expression for r = 1. cos( θ) = x/1 = x. Therefore, when r = 1, we have cos( θ) =x.