Core Connections Integrated II, 2015
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Core Connections Integrated II, 2015 View details
1. Section 4.1
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Exercise 53 Page 229

Practice makes perfect
a Let's first make the table by putting in some value of x into the given equation.

|c|c|c| [-1em] x & x^2 & y [0.2em] [-1em] -2 & ( -2)^2 & 4 [0.2em] [-1em] -1 & ( -1)^2 & 1 [0.2em] [-1em] 0 & 0^2 & 0 [0.2em] [-1em] 1 & 1^2 & 1 [0.2em] [-1em] 2 & 2^2 & 4 [0.2em] When we know a few points through which the functions passes, we can graph the function.

b Let's first make the table.

|c|c|c| [-1em] x & - x^2 & y [0.2em] [-1em] -2 & -( -2)^2 & - 4 [0.2em] [-1em] -1 & -( -1)^2 & -1 [0.2em] [-1em] 0 & - 0^2 & 0 [0.2em] [-1em] 1 & - 1^2 & -1 [0.2em] [-1em] 2 & - 2^2 & -4 [0.2em] When we know a few points through which the functions passes, we can graph the function.

c Let's put the graphs in the same coordinate plane so we can compare them more easily.

If we compare a few points on the graphs that lie on the same x-coordinate, we notice that the segments between them are equidistant from and perpendicular to the x-axis.

As we can see, the two graphs are mirror images of each other in the x-axis.

d To estimate the x-values when y=5, we should draw y=5 in the coordinate plane from Part A and determine where the two two functions intersect.

As we can see, the x-values corresponding to y=5 is x≈ -2.2 and x≈ 2.2.

e To estimate the x-values when y=-10, we should draw y=-10 in the coordinate plane from Part B and determine where the two functions intersect.

As we can see, the x-values corresponding to y=-10 is x≈ -3.2 and x≈ 3.2.