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Core Connections Integrated II, 2015

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Core Connections Integrated II, 2015 View details

1. Section 4.1

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Exercise 29 Page 220

The distance we can calculate with the given values will be 1.5 meter short of the building's real height.

≈ 330.4 meter

Practice makes perfect

Let's illustrate the situation in a diagram. We will label the height of the Space Needle x. Note that this diagram is not drawn to scale.

With the given information, we can calculate the vertical distance x between Salvador's eyes and the top of the building using the tangent ratio.

tan θ=opposite/adjacent Let's identify the opposite and adjacent leg to the given angle in our diagram.

Let's solve for x in this equation.

tan80=x/58

LHS * 58=RHS* 58

58tan80=x

Rearrange equation

x=58tan80

Use a calculator

x =328.93434...

Round to 1 decimal place(s)

x ≈ 328.9

The distance between Salvador's eyes and the top of the Space Needle is about 328.9 meters. To obtain the building's total height from the ground, we have to add the distance between the ground and Salvadors's eyes. 328.9+1.5=330.4 meter

Subchapter links

4.1.1 Introduction to Factoring Expressions p.213-214

4.1.2 Introduction to Factoring Expressions p.217-218

4.1.3 Factoring More Quadratics p.220-221

4.1.4 Factoring Completely p.225-226

4.1.5 Factoring Special Cases p.228-229