Core Connections Integrated II, 2015
CC
Core Connections Integrated II, 2015 View details
1. Section 4.1
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Exercise 32 Page 221

Practice makes perfect
a In this diamond we have been given the values of x and y.
&x= 1/2 &y= 1/2

Let's determine xy and x+y by substituting these values into the expressions. xy:& 1/2( 1/2)=1/4 x+y:& 1/2+ 1/2=1 Now we can complete our diamond!

b Like in Part A, we have been given the values of x and y.
&x= 1/3 &y= 3/4

Let's determine xy and x+y by substituting these values into the expressions. xy:& 1/3( 3/4)=1/4 x+y:& 1/3+ 3/4=13/12 Now we can complete our diamond!

c Like in Parts A and B, we have been given the values of x and y.
&x= x &y= x

Let's determine xy and x+y by substituting these values into the expressions. xy:& x( x)=x^2 x+y:& x+ x=2x Now we can complete our diamond!

d Like in Parts A through C, we have been given the values of x and y.
&x= a &y= b

Let's determine xy and x+y by substituting these values into the expressions. xy:& a( b)=ab x+y:& a+ b Now we can complete our diamond!