Core Connections Integrated II, 2015
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Core Connections Integrated II, 2015 View details
1. Section 4.1
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Exercise 50 Page 228

Practice makes perfect
a Look closely at the expression x^2-64. It can be expressed as the difference of two perfect squares.
x^2-64
x^2-8^2
Recall the formula to factor a difference of squares. a^2- b^2 ⇔ ( a+ b)( a- b) We can apply this formula to our expression. x^2- 8^2 ⇔ ( x+ 8)( x- 8)
b To determine if an expression is a perfect square trinomial, we need to ask ourselves three questions.
Is the first term a perfect square? x^2= x^2 âś“
Is the last term a perfect square? 9= 3^2 âś“
Is the middle term twice the product of 3 and x? 6x=2* 3* x âś“

As we can see, the answer to all three questions is yes! Therefore, we can write the trinomial as the square of a binomial. Note there is a subtraction sign in the middle. ( x^2-6x+9) ⇔ ( x- 3)^2

c To determine if an expression is a perfect square trinomial, we need to ask ourselves three questions.
Is the first term a perfect square? 4x^2= 2^2x^2=( 2x)^2 âś“
Is the last term a perfect square? 1= 1^2 âś“
Is the middle term twice the product of 1 and 2x? 4x=2* 1* 2x âś“

As we can see, the answer to all three questions is yes! Therefore, we can write the trinomial as the square of a binomial. Note there is an addition sign in the middle. ( 4x^2+4x+1) ⇔ ( 2x+ 1)^2

d Look closely at the expression 4x^2-49. It can be expressed as the difference of two perfect squares.
4x^2-49
2^2x^2-7^2
(2x)^2-7^2
Recall the formula to factor a difference of squares. a^2- b^2 ⇔ ( a+ b)( a- b) We can apply this formula to our expression. ( 2x)^2- 7^2 ⇔ ( 2x+ 7)( 2x- 7)