Core Connections Integrated II, 2015
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Core Connections Integrated II, 2015 View details
1. Section 10.1
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Exercise 42 Page 560

Practice makes perfect
a Before we can find the inverse of the given function, we need to replace f(x) with y.
f(x)=x/3-2 ⇔ y=x/3-2Now, to algebraically determine the inverse of the given equation we exchange x and y and solve for y. Given Equation & Inverse Equation y=x/3-2 & x=y/3-2 The result of isolating y in the new equation will be the inverse of the given function.
x=y/3-2
â–Ľ
Solve for y
x+2=y/3
3x+6=y
y=3x+6
Finally, we write the inverse of the given function in function notation by replacing y with f^(- 1)(x) in our new equation. f^(- 1)(x)=3x+6
b Before we can find the inverse of the given function, we need to replace g(x) with y.
g(x)=1/2x+5 ⇔ y=1/2x+5Now, to algebraically determine the inverse of the given equation, we exchange x and y and solve for y. Given Equation & Inverse Equation y=1/2 x+5 & x=1/2 y+5 The result of isolating y in the new equation will be the inverse of the given function.
x=1/2y+5
â–Ľ
Solve for y
x-5=1/2y
2x-10=y
y= 2x-10
Finally, we write the inverse of the given function in function notation by replacing y with g^(- 1)(x) in our new equation. g^(- 1)(x)=2x-10