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Equate the sum of the angles' expressions with the sum of the interior angles of a pentagon.
4/5
Let's first find the measure of each angle. To determine the sum of the interior angles in a polygon, we use the formula 180^(∘)(n-2) where n is the number of sides.
n= 5
Subtract term
Multiply
Remove parentheses
Add and subtract terms
LHS-90^(∘)=RHS-90^(∘)
.LHS /15.=.RHS /15.
When we know that x= 30^(∘) we can find the measure of each angle. 3( 30^(∘))-26^(∘)& = 64^(∘) 2( 30^(∘))+70^(∘)& = 130^(∘) 5( 30^(∘))-10^(∘)& = 140^(∘) 3( 30^(∘))& = 90^(∘) 2( 30^(∘))+56^(∘)& = 116^(∘) As we can see, 4 of 5 angles are greater than or equal to 90^(∘). Therefore, the probability of selecting an angle that is more than or equal to 90^(∘) must be 4 5.