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From the table, we see that y= 3 when x=0, which limits the equations it could be to (3) and (6). (3) y&=x + 3 (6) y&=x^2+ 3 Next, we have to determine if the function is linear or quadratic. If it is linear, the function will have a constant rate of change between consecutive numbers. Let's plot the points in the table of values.
Examining the diagram, we see that the data points follow a linear pattern, which means the table should be paired with (3) y=x+3.
From the table, we see that y=0 when x=0, which limits the functions it could be to (1), (4), and (6). Notice that when the constant is zero, its usually not written out. (1) y&= x (4) y&= x^2 (5) y&=- x^2 Like in Part A, we will plot the point in a coordinate plane.
Examining the diagram, we see that the data points make a parabola that opens downwards. This means the coefficient to x^2 must be negative, and therefore we should pair it with (5).
From the table, we see that y= 3 when x=0, which limits the functions it could be to (3) and (6). (3) y&=x + 3 (6) y&=x^2+ 3 However, we have already paired (3) with the first table and therefore we must pair this table with the remaining quadratic option, (6) y=x^2+3. For good measure, we will plot the points to make sure it resembles a parabola.
& ↓ & |c|c|c|c|c|c|c| x & -3 & 4 & 2 & -2 & 0 & -10 y & - 10 & 11 & 5 & -7 & -1 & - 31 There is only one equation with a y-intercept of -1, and that is (2) y=3x-1. For good measure, we will plot the data points to make sure they resemble a linear equation.