Core Connections Integrated II, 2015
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Core Connections Integrated II, 2015 View details
2. Section 1.2
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Exercise 38 Page 25

Practice makes perfect
a The x-intercept is the point where the graph intercepts the x-axis. This happens when y=0. Let's substitute this in the equation and solve for x.
y=1/2x-4
0=1/2x-4
â–Ľ
Solve for x
4=1/2x
8=x
x=8
The x-intercept is at x=8.
b We can make a table by substituting different values of x in the equation and simplifying.

|c|c|c| [-1em] x & 1/2x-4 & y [0.7em] [-0.8em] 0 & 1/2( 0)-4 & - 4 [0.7em] [-0.8em] 2 & 1/2( 2)-4 & - 3 [0.7em] [-0.8em] 4 & 1/2( 4)-4 & - 2 [0.7em] Note that we only need two points to draw the graph. With that said, we will plot all three points.

c Having graphed the equation in Part B, we can find the x-intercept by examining where the graph crosses the x-axis. In this case, it does so at a lattice point, which makes this possible. However, if the x-intercept was a decimal number, this would not be a viable option.

To find the x-intercept with a table, we have to try x-values at random until we get lucky and choose the x-value that produces y=0.