Core Connections Integrated II, 2015
CC
Core Connections Integrated II, 2015 View details
2. Section 1.2
Continue to next subchapter

Exercise 51 Page 31

Practice makes perfect
a To find the area of a rectangle, we multiply its length l and width w.
A= l w Let's first name the rectangles.

Multiplying the length and width of each rectangle, we get the following.

Rectangle l w l w A
a 7 11 ( 7)( 11) 77
b 7 8 ( 7)( 8) 56
c 3 11 ( 3)( 11) 33
d 3 8 ( 3)( 8) 24

The areas of the rectangles are 77, 56, 33, and 24 square units, respectively. To find the area of the whole rectangle, we have to add all of these. 77+56+33+24=190 The whole area is 190 square units.

b To find the area of a rectangle, we multiply its length l and width w.
A= l w Let's first name the rectangles.

Multiplying the length and width of each rectangle, we get the following.

Rectangle l w l w A
a 11x 3x ( 11x)( 3x) 33x^2
b 11x -4 ( 11x)( -4) -44x
c -2 3x ( -2)( 3x) -6x
d -2 -4 ( -2)( -4) 8

The areas of the rectangles are 33x^2, -44x, -6x, and 8 square units, respectively. To find the area of the whole rectangle, we have to add all of these. 33x^2+(-44x)+(-6x)+8 = 33x^2-50x+8