Core Connections Geometry, 2013
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Core Connections Geometry, 2013 View details
2. Section 6.2
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Exercise 74 Page 375

Practice makes perfect
a The two angles are complementary as they form a right angle when added.
Therefore, we can set the sum of their expressions equal to 90^(∘). (18x-10^(∘) )+7x=90^(∘) Let's solve this equation for x
(18x-10^(∘))+7x=90^(∘)
Solve for x
18x-10^(∘)+7x=90^(∘)
25x-10^(∘)=90^(∘)
25x=100^(∘)
x=4^(∘)
b The triangle in the diagram is an isosceles triangle. By the Base Angles Theorem, we know that it has two congruent base angles.
We also see that the 110^(∘) angle is exterior angle to the triangle's vertex angle. By the Exterior Angles Theorem, the measure of the exterior angle equals the sum of the measures of the nonadjacent interior angles. With this information we can write and solve an equation for x.
x+x=110
2x=110^(∘)
x=55^(∘)
c In the given diagram, we can identify a pair of consecutive interior angles as well as a pair that forms a straight angle.
Since the two lines cut by the transversal are parallel, the consecutive interior angles are supplementary. Additionally, two angles that form a straight angle must also be supplementary. With this, we can write two equations. (5x+2^(∘))+63^(∘) = 180^(∘) (3y-12^(∘))+63^(∘) = 180^(∘) Let's solve for x in the first equation.
(5x+2^(∘))+63^(∘) = 180^(∘)
Solve for x
5x+2^(∘)+63^(∘) = 180^(∘)
5x+65^(∘) = 180^(∘)
5x = 115^(∘)
x = 23^(∘)
Let's solve for y in the second equation.
(3y-12^(∘))+63^(∘) = 180^(∘)
Solve for y
3y-12^(∘)+63^(∘) = 180^(∘)
3y+51^(∘) = 180^(∘)
3y=129^(∘)
y = 43^(∘)
d The two base angles are equal. This means that the legs are congruent by the Converse of the Base Angles Theorem.
Let's solve this equation for x.
3x+13=5x+2
Solve for x
13=2x+2
11=2x
5.5=x
x=5.5
To find y, we will first have to find the vertex angle and the length of the sides that contain x-expressions. Since we know that the base angles are both 40^(∘), we can use the Interior Angles Theorem to find the measure of the vertex angle. θ +40^(∘) +40^(∘)=180^(∘) ⇔ θ =100^(∘) We can use either expression and that x= 5.5 to find the missing side lengths. c 3 x+13=5 x+2 3( 5.5)+13=5( 5.5)+2 29.5=29.5 Now that we know the vertex angle and the side lengths, we can calculate the side labeled y by using the Law of Sines.
Let's solve for y in this equation.
sin(40^(∘))/29.5=sin(100^(∘))/y
y*sin(40^(∘))/29.5=sin(100^(∘))
ysin(40^(∘))=29.5sin(100^(∘))
y=29.5sin(100^(∘))/sin(40^(∘))
y=45.196622...
y≈ 45.2