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Diagram:
Linear:& y=2x+5 [0.7em] Quadratic:& y=2x^2+5 [0.3em] Quadratic:& y=1/2x^2+5 To graph the linear equation, we need at least two points. The first point, we can find by plotting its y-intercept, (0,5). To plot a second point, we can use the function's slope which is what the 2 represents.
Let's continue by drawing the graph of the first quadratic. For this purpose, we need to make a table of values. |c|c|c| [-0.8em] x & 2x^2+5 & y [0.2em] [-0.8em] -2 & 2( -2)^2+5 & 13 [0.2em] [-0.8em] -1 & 2( -1)^2+5 & 7 [0.2em] [-0.8em] 0 & 2( 0)^2+5 & 5 [0.2em] [-0.8em] 1 & 2( 1)^2+5 & 7 [0.2em] [-0.8em] 2 & 2( 2)^2+5 & 13 [0.2em] Let's mark these points in our diagram and draw a parabola through them.
Let's continue by drawing the last quadratic. For this purpose, we need to make another table of values. |c|c|c| [-0.8em] x & 1/2x^2+5 & y [0.8em] [-0.8em] -4 & 1/2( -4)^2+5 & 13 [0.8em] [-0.8em] -2 & 1/2( -2)^2+5 & 7 [0.8em] [-0.8em] 0 & 1/2( 0)^2+5 & 5 [0.8em] [-0.8em] 2 & 1/2( 2)^2+5 & 7 [0.8em] [-0.8em] 4 & 1/2( 4)^2+5 & 13 [0.8em] Finally, we will plot the function's graph by marking the points in the diagram and connecting them with a smooth curve.
Examining the diagram, we notice that all three graphs intersect the y-axis at y=5. We also see that the red function intersect the x-axis at x=-2.5.