Core Connections Algebra 2, 2013
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Core Connections Algebra 2, 2013 View details
1. Section 2.1
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Exercise 61 Page 78

Practice makes perfect
a The distance traveled d during a certain time t and with a given speed r can be calculated by using the following formula.
d=rtFrom the exercise, we know that Lettie drives with a speed of 80 mph and that she travels 50 miles. By substituting these values into the exercise, we can solve for t.
d=rt
50= 80t
80t=50
x=0.625
It takes her 0.625 hours to travel the given distance at the speed at which she is driving. If we want this number in minutes, we must multiply by 60. 0.625* 60 = 37.5minutes
b Let's repeat the calculations from Part A, but switch the speed from 80 to 65.
d=rt
50= 65t
65t=50
x=0.76923...
x≈ 0.769
It takes her 0.769 hours to travel the given distance at the speed limit. Again, to get this number in minutes, we must multiply by 60. 0.769* 60 ≈ 46minutes
c Let's restate the times it took to travel with the different speeds.

80 mph:& 37.5 minutes 65 mph:& 46 minutes As we can see, Lettie saved 8.5 minutes by going faster. To calculate the fine per minute, we have to divide the amount of the fine with the total number of minutes she saved. $200/8.5≈ $23.50 She paid $23.50 for every minute she saved.