Core Connections Algebra 2, 2013
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Core Connections Algebra 2, 2013 View details
1. Section 2.1
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Exercise 10 Page 59

Substitute the given information into the Slope Formula and solve for the variable term.

The value of n: 24
Distance: ≈ 25.495

Practice makes perfect

We are given the slope between two points and asked to find one of the coordinates of the second point and the distance between these points. To do that we will use two formulas: the Slope Formula and the Distance Formula.

The value of n

The Slope Formula is used to determine the slope m of the line that connects two given points, ( x_1, y_1) and ( x_2, y_2). m=y_2- y_1/x_2- x_1 In this case, however, we have been given the slope of a line and two points with one missing coordinate. When we substitute these values into the Slope Formula, it does not matter which point we choose to use as ( x_1, y_1) or ( x_2, y_2). Both will give the same result. 5=n-( -1)/2-( -3) or 5=-1- n/-3- 2 Here we will use the points in the given order and solve for the unknown coordinate.
m = y_2-y_1/x_2-x_1
m=n-( -1)/2-( -3)
5=n-(-1)/2-(-3)
Solve for n
5=n+1/2+3
5=n+1/5
25=n+1
24=n
n=24
When n=24, the line passes through both points.

Distance

To find the distance between two points we can use the Distance Formula. AB=sqrt(( x_2- x_1)^2+( y_2- y_1)^2) Let's substitute A(-3,-1) and B=(2,24) into above formula.
AB=sqrt((x_2-x_1)^2+(y_2-y_1)^2)
AB=sqrt(( 2-( -3))^2+( 24-( -1))^2)
Simplify
AB=sqrt((2+3)^2+(24+1)^2)
AB=sqrt((5)^2+(25)^2)
AB=sqrt(25+625)
AB=sqrt(650)
AB=25.49509...
AB≈25.5
The distance between A and B is approximately 25.5.