Core Connections Algebra 2, 2013
CC
Core Connections Algebra 2, 2013 View details
1. Section 2.1
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Exercise 8 Page 59

Practice makes perfect
a The sequence could either be arithmetic or geometric. Examining the difference between consecutive terms, we notice that the change is not linear which precludes an arithmetic sequence. Let's test if its geometric.
Since a common ratio separates consecutive terms, the sequence is in fact geometric. To find the next three terms, we can just continue the sequence.
The general form of a geometric sequence can be written in the following format. a_n=a_0b^n In this equation, a_0 is the zeroth term and b is the common ratio. By substituting the values of b and a_1, we can solve for the zeroth term.
a_n=a_0b^n
a_1=a_0( 0.25)^1
256=a_0(0.25)^1
â–Ľ
Solve for a_0
256=a_0(0.25)
1024=a_0
a_0=1024
The equation can be written as a_n=1024(0.25)^n.
b If we continue writing more terms in the series, we can use the equation a_n=1024* 0.25^n to see what will happen to the terms. As n gets larger, the term 0.25^n will get start to approach zero which means the sequence will get continuously smaller. However, the sequence will never be 0 as that would require us to multiply by 0
c From Part A, we have calculated the first six data point in the sequence. Let's plot these in a coordinate plane.

As we move to the right the sequence approaches the x-axis.

d The domain of the sequence is the set of all values n can take on. For this sequence, the domain is 1, 2, 3, 4..., which we also know as the natural numbers.

Domain Sequence: {1,2,3,4, ... } The function with the same equation as the sequence can be written as y=1024(0.25)^x. Since the sequence begins with n=1 we let the function begin at x=1 as well. In this function, any real number greater than or equal to 1 is permitted. Therefore, the function will have the following domain. Domain Function: x≥ 1