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Core Connections Algebra 1, 2013

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Core Connections Algebra 1, 2013 View details

2. Section 1.2

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Exercise 41 Page 21

Practice makes perfect

a Let's substitute x=16 in the equation and calculate y.

y=3+sqrt(x-8)

x= 16

y=3+sqrt(16-8)

Subtract term

y=3+sqrt(8)

Calculate root

y=3+2

Add terms

y=5

The value of the equation is 5 when x=16.

b Similar to Part A, we substitute x=16 into the equation.

y=sqrt(x)-7

x= 16

y=sqrt(16)-7

Calculate root

y=4-7

Subtract term

y=- 3

The value of the equation is - 3 when x=16.

c Similarly to Parts A and B, we substitute x=16 into the equation.

y=4+|9-x|

x= 16

y=4+|9- 16|

Subtract term

y=4+|- 7|

|-7|=7

y=4+7

Add terms

y=11

The value of the equation is 11 when x=16.

Subchapter links

1.2.1 Describing a Graph p.19-21

1.2.2 Cube Root and Absolute Value Functions p.23-24

1.2.3 Function Machines p.27

1.2.4 Functions p.30-31

1.2.5 Domain and Range p.36