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Create a table of values and remember that sqrt(x) only equals an integer for perfect cubes, x^3=x* x* x.
Description: See solution.
Graph:
1^3& =1 * 1 *1 =1 2^3& =2 * 2 *2 =8 3^3& =3 * 3 *3 =27 4^3& =4 * 4 *4 =64 We can use the positives and negatives of these values to create the table. |c|c|c|c| [-0.5em] x & sqrt(x)-2 & Write as a Cube & y [0.5em] [-1em] -64 & sqrt(-64)-2 & sqrt((-4)^3)-2 & - 6 [0.5em] [-1em] -27 & sqrt(-27)-2 & sqrt((-3)^3)-2 & - 5 [0.5em] [-1em] -8 & sqrt(-8)-2 & sqrt((-2)^3)-2 & - 4 [0.5em] [-1em] -1 & sqrt(-1)-2 & sqrt((-1)^3)-2 & - 3 [0.5em] [-1em] 0 & sqrt(0)-2 & sqrt(0^3)-2 & - 2 [0.5em] [-1em] 1 & sqrt(1)-2 & sqrt(1^3)-2 & - 1 [0.5em] [-1em] 8 & sqrt(8)-2 & sqrt(2^3)-2 & 0 [0.5em] [-1em] 27 & sqrt(27)-2 & sqrt(3^3)-2 & 1 [0.5em] [-1em] 64 & sqrt(64)-2 & sqrt(4^3)-2 & 2 [0.5em] We will graph the function by plotting the (x,y) points from the table.
To describe the graph above, we can use the description guidelines from the previous exercise.