Core Connections Algebra 1, 2013
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Core Connections Algebra 1, 2013 View details
2. Section 1.2
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Exercise 51 Page 24

Use the given pattern to complete each of the diamonds.


A.

B.

C.

D.

Practice makes perfect

To find the missing numbers, let's identify the variables using our variable diamond and substitute the correct numbers into our pattern.

Diamond A

In Diamond A, we are given values for A and B, and we want to find C and D. A= 1/2 and B=1/2 To do this, we can substitute the numbers in our pattern.
C= A * B D=A+B

(I), (II): A= 1/2, B= 1/2

C= 12 * 12 D= 12+ 12
C= 14 D= 12+ 12
C= 14 D=1

Now we can complete our first diamond.

Diamond B

In Diamond B, again we are given values for A and B, and we want to find C and D. A= 1/3 and B=3/4 To do this, we can substitute the numbers in our pattern.
C= A * B D=A+B

(I), (II): A= 1/3, B= 3/4

C= 13 * 34 D= 13+ 34
C= 1*33*4 D= 13+ 34
C= 14 D= 13+ 34
â–Ľ
(II):Add fractions
C= 14 D= 412+ 34
C= 14 D= 412+ 912
C= 14 D= 4+912
C= 14 D= 1312
â–Ľ
(II):Write fraction as a mixed number
C= 14 D= 12+112
C= 14 D= 1212+ 112
C= 14 D=1+ 112
C= 14 D=1 112
We can now complete our second diamond.

Diamond C

Again we are given values for A and B, and we want to find C and D. A= x and B=x To do this, we can substitute the numbers in our pattern.
C= A * B D=A+B

(I), (II): A= x, B= x

C= x * x D= x+ x
C=x^2 D=x+x
C=x^2 D=2x
Now we can complete our third diamond.

Diamond D

Here we are also given values for A and B, and we want to find C and D. A= a and B=b To do this, we can substitute the numbers in our pattern.
C= A * B D=A+B

(I), (II): A= a, B= b

C= a * b D= a+ b
C=ab D=a+b