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Core Connections Algebra 1, 2013

CC

Core Connections Algebra 1, 2013 View details

2. Section 1.2

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Exercise 66 Page 30

Substitute x with the given value.

g(8)=1
g(32)=5
g(80)=sqrt(73)

Practice makes perfect

To find g(8), we substitute x=8 in g(x)=sqrt(x-7) and evaluate the right-hand side.

g(x)=sqrt(x-7)

x= 8

g( 8)=sqrt(8-7)

Subtract term

g(8)=sqrt()1

Calculate root

g(8)=1

Let's do the same for the rest of the values.

x	sqrt(x-7)	g(x)
32	sqrt(32-7)	5
80	sqrt(80-7)	sqrt(73)

Subchapter links

1.2.1 Describing a Graph p.19-21

1.2.2 Cube Root and Absolute Value Functions p.23-24

1.2.3 Function Machines p.27

1.2.4 Functions p.30-31

1.2.5 Domain and Range p.36