Exercise 49 Page 24

Practice makes perfect

a To solve the equation, we have to isolate x on one side of the equation by performing inverse operations.

3x+7=- x-1

AddEqn

LHS+x=RHS+x

4x+7=-1

SubEqn

LHS-7=RHS-7

4x=-8

DivEqn

.LHS /4.=.RHS /4.

x=-2

b Again, to solve the equation, we have to isolate x on one side of the equation.

1-2x+5=4x-3

AddTerms

Add terms

6-2x=4x-3

SubEqn

LHS-4x=RHS-4x

6-6x=-3

SubEqn

LHS-6=RHS-6

-6x=-9

MultEqn

LHS * (- 1)=RHS* (- 1)

6x=9

DivEqn

.LHS /6.=.RHS /6.

x=9/6

ReduceFrac

a/b=.a /3./.b /3.

x=3/2

c Once more, we solve the equation by isolating x on one side of the equation.

4x-2+x=-2+2x

AddTerms

Add terms

5x-2=-2+2x

SubEqn

LHS-2x=RHS-2x

3x-2=-2

AddEqn

LHS+2=RHS+2

3x=0

DivEqn

.LHS /3.=.RHS /3.

x=0

d Let's try to isolate x.

3x-4+1=-2x-5+5x

AddTerms

Add terms

3x-3=3x-5

SubEqn

LHS-3x=RHS-3x

-3 ≠ -5

Attempting to solve the equation, we get a contradiction. This means the equation has no solution.

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