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| Student Learning Objectives: |
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| | 11 Theory slides |
| | 6 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Ignacio needs to determine if the following segments are congruent to each other. However, he only has a piece of string and a pencil. Is he able to do it? If so, how?
Show Pencilbutton. Then, move the pencil tip over the place to mark. Finally, release the click.
A natural history museum manager hopes to place a replica of a moai statue in a triangular room in such a manner that the statue is equidistant from the walls that will have detailed diagrams and explanations. The location of the statue corresponds to the incenter of the triangle formed by the walls. This placement will allow for a clear walking path.
When copying a segment using a straightedge and compass, the function of the compass is to measure the length of the segment. With this in mind, a string can be a good substitute for the compass.
Using a straightedge and a string, it is possible to construct a copy of a segment.
The following three steps can be used to draw a segment with the same length as AB.
The marked point on the string indicates the location of B'. Then, mark this point on A'C and label it as B'.
Finally, by erasing the unnecessary part of A'C, a segment whose length is the same as the length of AB will be obtained.
As can be seen, AB and A'B' are copies of each other.
Using a straightedge and a string, it is possible to construct a copy of an angle.
The following five steps can be used to draw an angle whose measure is equal to the measure of ∠ ABC.
Next, holding down the end that is on B, stretch the string. Keeping the string stretched, make an arc that intersects the sides of ∠ ABC. Let P and Q be these points of intersection.
Finally, move the free end of the string to E and draw an arc centered at E. Let D be the intersection point between the ray and the arc.
Then, mark the point on the string that is on Q and tie the pencil to the string so that its tip is over the mark. It is not a necessity, but the remaining part of the string can be removed.
Paper folding, also referred to as origami, provides an alternative method for making constructions when tools such as a compass are not on hand.
An angle can be bisected using only a straightedge and folding the paper.
To bisect ∠ ABC, the following two steps can be done. If available, it is recommended to use tracing paper.
Using the folding paper technique, the challenge presented at the beginning of the lesson can be solved. A natural history museum manager hopes to place a replica of a moai statue in a triangular room in such a manner that the statue is equidistant from the walls that will have detailed diagrams and explanations. The location of the statue corresponds to the incenter of the triangle formed by the walls. This placement will allow for a clear walking path.
The manager's son, Kevin, sees the blueprint and wants to help to locate the incenter. Unfortunately, he does not have a protractor. Can he locate the incenter on the blueprint? If so, how?
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Incenter |
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The incenter of a triangle is the point of intersection of the triangle's angle bisectors. |
To obtain the point of intersection, Kevin needs to draw at least two angle bisectors to locate the incenter. To do so, begin by labeling the vertices of the triangle.
To draw the angle bisector of ∠ A, fold the blueprint so that AB lies on AC. Once the blueprint is unfolded, the crease made will represent the angle bisector.
To draw the angle bisector ∠ C, the blueprint has to be folded so that AC lies on BC. That way, a second crease will be made in the blueprint, representing the angle bisector of ∠ C.
The point where the two creases intersect each other corresponds to the incenter of the triangle. Consequently, this is the location where the moai replica has to be placed.
Notice that, thanks to the Incenter Theorem, the angle bisector of ∠ B does not have to be drawn to locate the incenter.
The usual way to draw the perpendicular bisector of a segment involves a straightedge and a compass. However, the same construction can be done without a compass.
Given a segment drawn on a paper, its perpendicular bisector can be drawn only using a straightedge and a pencil.
To draw the perpendicular bisector of AB, the following two steps can be used. If available, tracing paper is recommended.
Math teacher by day, the world's greatest futsal coach by night, Coach Tiffaniqua drew the following formation on a board to teach her players where to position themselves when taking a free kick near the court's center.
Ali, ecstatic, asked where he should be in the formation. Coach Tiffaniqua told Ali that he should be positioned the same distance from Diego, Ignacio, and Kevin. Determine where Ali should be positioned on the futsal field.
By definition, the circumcenter of a triangle is equidistant from the vertices. Therefore, to know where Ali should be placed, find the circumcenter of △ KDI. To do so, begin by drawing this triangle on a piece of paper.
Since the circumcenter is the point of intersection of the triangle's perpendicular bisectors, at least two perpendicular bisectors need to be drawn. Start by drawing the perpendicular bisector of KD. To do it, fold the paper so that K matches D.
Then, draw the perpendicular bisector of KI by folding the paper so that K and I match.
The circumcenter of △ KDI is the point where the two creases intersect each other. Finally, place the paper over the board and mark the circumcenter on it. This is the position where Ali should be positioned.
The last construction of this lesson will be to draw a line perpendicular to a given line through a point that is not on the line. Of course, this can be done using a straightedge and compass. However, it is possible to do so without the use of a compass.
A line perpendicular to a given line through a point not on the line can be drawn by using only a straightedge and a pencil.
To draw a line perpendicular to AB through P the following two steps can be used.
Ali has a piece of paper with an acute triangle drawn on it. He wants to draw the orthic triangle corresponding to △ ABC whose vertices are the feet of the altitudes of △ ABC.
However, Ali does not have a compass at hand. Help Ali draw the desired triangle.
Using the same method, the altitudes from B and C can also be drawn.
This construction gives the feet of the altitudes and the orthocenter of △ ABC. Finally, draw the orthic triangle by connecting A', B', and C'.
Before finishing the lesson, two interesting facts about the orthic triangle — also called the pedal triangle.
To have the same area, the triangles with the same base must have the same corresponding altitude. The diagram shows that one pair of sides are marked as congruent. Therefore, if we measure the length of the altitudes from these sides to their opposite vertices, we can determine if the triangles have the same area.
Given what we now know, we only have to make two measurements — one for each altitude — to determine if the triangles have the same area.
To find the altitudes of each triangle, we must fold the paper along the opposite vertex of the two sides marked as congruent such that AC traces onto itself and DE also traces onto itself.
Let's start by finding the altitude from B.
Next, we will create the altitude from F.
Having found the altitudes, we can use the string to measure them. Place the string along BX and mark the altitude on the string.
Finally, we move the string such that it traces FY. If the altitudes are the same, the marked point on the string should coincide with either Y or F.
As we can see, the altitudes are not the same. This means the triangles do not have the same area.
Which of the point(s), A through F, are on the angle bisector of ∠ X?
To find the angle bisector of ∠ X, fold the paper such that X is on the fold and XY traces XZ. The crease shows us the angle bisector. Let's fold XY such that it traces XZ.
Now we see that A, C, and E are on the angle bisector. However, for good measure, let's unfold the paper revealing the angle bisector.
Which of the point(s), A through F, fall on the perpendicular bisector of l?
The perpendicular bisector of a segment cuts it in two equal halves at a right angle. To do this, we can fold the paper such that the endpoints of l map onto each other. The crease creates the perpendicular bisector of l.
As we can see, C and E fall on the perpendicular bisector of l. For good measure, we will unfold the paper revealing the perpendicular bisector.