Big Ideas Math: Modeling Real Life, Grade 8
BI
Big Ideas Math: Modeling Real Life, Grade 8 View details
2. The Pythagorean Theorem
Continue to next subchapter

Exercise 26 Page 387

57 feet

Practice makes perfect

Let's look at the given diagram!

Golf park with the distance between the tee and the hole is 180 yards and a close up on a hole with a 90 degree turn and the text in the corner Hole 13, Par 3, 181 yards

We can see on the diagram that the distance from the tee to the location of the ball after the tee shot is 180 yards. We also know that the distance from the tee to the 13th hole is 181 yards and the distance from the ball to the 13th hole is marked with the variable x. Now, we can draw a triangle with sides that measure 180 yards, 181 yards, and x yards. Let's do it!

triangle with the tee, ball and hole as vertices

Notice that the missing side is one leg of a right triangle. This means that we can use the Pythagorean Theorem to find x. a^2+b^2=c^2 In the formula, a and b are the legs and c is the hypotenuse of a right triangle. Let's identify a, b, and c on the diagram.

triangle with marekd sides
We can see that a is 180 yards, b is x yards, and c is 181 yards. Let's substitute these values into the formula!
a^2+b^2=c^2
180^2+ x^2= 181^2
â–Ľ
Solve for x
32 400+x^2=32 761
x^2=361
sqrt(x^2)=sqrt(361)
x=sqrt(361)
x=19
The missing leg x is 19 yards long. This means that the ball is 19 yards from the hole. We want to find the distance from the ball to the hole in feet. To do so, we will convert 19 yards to feet. The conversion factor from yards to feet is 3ft1yd. 19yd* 3ft1yd We can simplify the expression for the distance from the ball to the hole.
19yd* 3ft/1yd
19 yd* 3ft/1 yd
19* 3ft/1
19* 3ft
57ft
The ball is 57 feet from the hole.