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Does either of the equations have an isolated variable in it?
(10,2)
In this system of equations, at least one of the variables has a coefficient of 1. Therefore, we will approach its solution with the Substitution Method. When solving a system of equations using this method, there are three steps.
Since the expression equal to x in the first equation is simpler, let's use that for our initial substitution.
(II):x= 5y
(II): Multiply
(II): LHS+10y=RHS+10y
(II): Add terms
(II): .LHS /11.=.RHS /11.
(II): a* b/c=a/c* b
(II): a/a=1
(II): Identity Property of Multiplication
(II): a/b=.a /11./.b /11.
(II): a/1=a
Great! Now, to find the value of x, we need to substitute y=2 into either one of the equations in the given system. Let's use the first equation.
The solution, or point of intersection, to this system of equations is the point (10,2).
To check our answer, we will substitute our solution into both equations. If doing so results in true statements, then our solution is correct.
(I), (II): x= 10, y= 2
(I), (II): Multiply
(II): Subtract term
Because both equations are true statements, we know that our solution is correct.