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Does either of the equations have an isolated variable in it?
(2,- 2)
When solving a system of equations using the Substitution Method, there are three steps.
For this exercise, y is already isolated in both equation, so we can skip straight to solving! Since the expression equal to y in (I) is simpler, let's use that for our initial substitution.
(II):y= x-4
(II):LHS-4x=RHS-4x
(II): Commutative Property of Addition
(II): Subtract terms
(II): LHS+4=RHS+4
(II): Add terms
(II): .LHS /(- 3).=.RHS /(- 3).
(II): a* b/c=a/c* b
(II): a/a=1
(II): Identity Property of Multiplication
(II): - a/- b=a/b
(II): Calculate quotient
Great! Now, to find the value of x, we need to substitute x=2 into the first equation.
The solution, or point of intersection, to this system of equations is the point (2,- 2).
To check our answer, we will substitute our solution into both equations. If doing so results in true statements, then our solution is correct.
(I), (II): x= 2, y= - 2
(II): Multiply
(I), (II): Subtract term
Because both equations are true statements, we know that our solution is correct.