Big Ideas Math: Modeling Real Life, Grade 8
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Exercise 21 Page 228

If we want to use the Elimination Method we should have at least one pair of variable terms with opposite coefficients.

See solution.

Practice makes perfect

Whenever we want to solve a system of equations we need to choose a method that we want to use. Sometimes one method seems to be easier to use when solving than others. Let's take a look at the example systems of linear equations.

System Method
y=2x-3 y=x+2 ?
x=6-y 2x+4y=10 ?
2x-4y=9 - 3x+4y=7 ?
In the first system both equations are in slope-intercept form. Therefore it might be easier to solve this system by graphing.
System Method
y=2x-3 y=x+2 Graphing
x=6-y 2x+4y=10 ?
2x-4y=9 -3x+4y=7 ?

In the second system, Equation 1 is solved for x. This means that we can use substitution and substitute the value of x into the other equation.

System Method
y=2x-3 y=x+2 Graphing
x=6-y 2x+4y=10 Substitution
2x-4y=9 -3x+4y=7 ?

Finally, in the third system one pair of variable terms have opposite coefficients. Therefore, the y-terms will eliminate each other when we add the equations, and elimination seems to be the easiest method.

System Method
y=2x-3 y=x+2 Graphing
x=6-y 2x+4y=10 Substitution
2x-4y=9 -3x+4y=7 Elimination

Summing up, it might be easier to solve a system of equations by elimination instead of graphing if it has at least one pair of variable terms with opposite coefficients.