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If we want to use the Elimination Method we should have at least one pair of variable terms with opposite coefficients.
See solution.
Whenever we want to solve a system of equations we need to choose a method that we want to use. Sometimes one method seems to be easier to use when solving than others. Let's take a look at the example systems of linear equations.
System | Method |
---|---|
y=2x-3 y=x+2 | ? |
x=6-y 2x+4y=10 | ? |
2x-4y=9 - 3x+4y=7 | ? |
System | Method |
---|---|
y=2x-3 y=x+2 | Graphing |
x=6-y 2x+4y=10 | ? |
2x-4y=9 -3x+4y=7 | ? |
In the second system, Equation 1 is solved for x. This means that we can use substitution and substitute the value of x into the other equation.
System | Method |
---|---|
y=2x-3 y=x+2 | Graphing |
x=6-y 2x+4y=10 | Substitution |
2x-4y=9 -3x+4y=7 | ? |
Finally, in the third system one pair of variable terms have opposite coefficients. Therefore, the y-terms will eliminate each other when we add the equations, and elimination seems to be the easiest method.
System | Method |
---|---|
y=2x-3 y=x+2 | Graphing |
x=6-y 2x+4y=10 | Substitution |
2x-4y=9 -3x+4y=7 | Elimination |
Summing up, it might be easier to solve a system of equations by elimination instead of graphing if it has at least one pair of variable terms with opposite coefficients.