Exercise 27 Page 385

In this exercise we want to use the given diagram to name a point that is collinear with points $E$ and $H.$ For a point to be collinear with two other points, it has to lie on the same line as these two points. Let's consider our diagram.

Note that points $E$ and $H$ are the front, bottom two corners of the cube and are not represented with any dots. For a point to be collinear with $E$ and $H,$ it would have to lie on line $\overleftrightarrow{EH}.$ Let's highlight $\overleftrightarrow{EH}$ in the diagram for a visual representation. We will also highlight the points lying on this line.

From the diagram, we can see that point $J$ is the only point, except for points $E$ and $H,$ that lies on line $\overleftrightarrow{EH}.$ It is, therefore, the only point that is collinear with $E$ and $H.$