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Big Ideas Math Integrated I, 2016

BI

Big Ideas Math Integrated I, 2016 View details

5. Measuring and Constructing Angles

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Exercise 63 Page 422

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

x=12

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side by using the Properties of Equality. In this case, we need to start by removing the parentheses to simplify the left-hand side of the equation.

(3x+15)+(4x-9)=90

Remove parentheses

3x+15+4x-9=90

Add and subtract terms

7x+6=90

Now we can continue to solve using the Properties of Equality.

7x+6=90

LHS-6=RHS-6

7x+6-6=90-6

Subtract terms

7x=84

.LHS /7.=.RHS /7.

7x/7=84/7

Calculate quotient

x=12

The solution to the equation is x=12.

Subchapter links

Communicate Your Answer p.413

Monitoring Progress p.414-418

Exercises p.419-422